20c^2+13cr-15r^2=

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Solution for 20c^2+13cr-15r^2= equation:


Simplifying
20c2 + 13cr + -15r2 = 0

Reorder the terms:
13cr + 20c2 + -15r2 = 0

Solving
13cr + 20c2 + -15r2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5c + -3r)(4c + 5r) = 0

Subproblem 1

Set the factor '(5c + -3r)' equal to zero and attempt to solve: Simplifying 5c + -3r = 0 Solving 5c + -3r = 0 Move all terms containing c to the left, all other terms to the right. Add '3r' to each side of the equation. 5c + -3r + 3r = 0 + 3r Combine like terms: -3r + 3r = 0 5c + 0 = 0 + 3r 5c = 0 + 3r Remove the zero: 5c = 3r Divide each side by '5'. c = 0.6r Simplifying c = 0.6r

Subproblem 2

Set the factor '(4c + 5r)' equal to zero and attempt to solve: Simplifying 4c + 5r = 0 Solving 4c + 5r = 0 Move all terms containing c to the left, all other terms to the right. Add '-5r' to each side of the equation. 4c + 5r + -5r = 0 + -5r Combine like terms: 5r + -5r = 0 4c + 0 = 0 + -5r 4c = 0 + -5r Remove the zero: 4c = -5r Divide each side by '4'. c = -1.25r Simplifying c = -1.25r

Solution

c = {0.6r, -1.25r}

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